How much of a pesticide with 10% active ingredient should be added to make 3 gallons of spray mixture if 2 oz of a.i. is required per gallon?

To determine how much of a pesticide with 10% active ingredient is needed for a 3-gallon spray mixture when 2 ounces of active ingredient (a.i.) are required per gallon, we first need to calculate the total amount of active ingredient required for the entire mixture.

Since each gallon requires 2 ounces of active ingredient, for 3 gallons, you will need:

[

2 , \text{oz/gallon} \times 3 , \text{gallons} = 6 , \text{oz of a.i.}

]

Next, since the pesticide solution is 10% active ingredient, we need to find out how much of the pesticide product to add to obtain the desired 6 ounces of active ingredient. If the pesticide is 10% active ingredient, this means that in every ounce of the pesticide solution, there is 0.1 ounces of active ingredient.

Let ( x ) be the total amount of pesticide solution needed. The equation to find this is:

[

0.10x = 6 , \text{oz of a.i.}

]

Solving for ( x ):

[

x = \frac{6 , \