A pesticide label states 2 oz of active ingredient is needed per gallon of spray mixture. How much of a 10% a.i. pesticide is needed to make 3 gallons of mix?

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To determine how much of a 10% active ingredient pesticide is required to prepare 3 gallons of a spray mixture, we first need to establish the total amount of active ingredient needed for that quantity of mixture.

The label specifies that 2 ounces of active ingredient are required per gallon of spray mixture. Since you're preparing 3 gallons, you would need:

2 oz/gallon × 3 gallons = 6 oz of active ingredient.

Next, because the pesticide formulation is 10% active ingredient, we must calculate how much of this formulation is needed to provide the 6 ounces of active ingredient.

A 10% solution means that for every 100 ounces of the solution, there are 10 ounces of active ingredient. To find out how much solution contains 6 ounces of active ingredient, you can set up the following calculation:

If 10% of X ounces equals 6 ounces of active ingredient, you can set up the equation:

0.10X = 6 ounces.

Solving for X gives:

X = 6 ounces / 0.10 = 60 ounces of the 10% pesticide solution.

Since we need 60 ounces of the solution and you want to express that in terms of ounces of the pesticide itself

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